Answer :
The given equation is 2(y-3)=4.
Opening the brackets implies,
2y-6=4
Move the y terms to LHS and constants to RHS implies,
[tex]\begin{gathered} 2y=10 \\ y=5 \end{gathered}[/tex]Therefore, the value of y is 5.
The given equation is 2(y-3)=4.
Opening the brackets implies,
2y-6=4
Move the y terms to LHS and constants to RHS implies,
[tex]\begin{gathered} 2y=10 \\ y=5 \end{gathered}[/tex]Therefore, the value of y is 5.