Answer :
[tex]\begin{gathered} PART\text{ A\rparen} \\ From\text{ the pic} \\ A_{base}=\frac{(4)(3)}{2}=\frac{12}{2}=6\text{ square units} \\ The\text{ area of each triangular base is 6 square units} \\ \\ PART\text{ B\rparen} \\ Surface\text{ area=2\lparen6\rparen+\lparen5+4+3\rparen\lparen2\rparen} \\ surface\text{ area=12+\lparen12\rparen\lparen2\rparen} \\ surface\text{ area =12+24} \\ suface\text{ area=36 square units} \\ The\text{ surface area is 36 square units} \end{gathered}[/tex]
