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Answer :

Explanation:

We are given: Ka1 = 8.0*10^-5

: Ka2 = 1.6*10^-12

: concentration = 0.240M

The value of Ka1>>Ka2, therefore Ka2 will not be considered in this calculations.

We then determine the concentration of H+ at equilibrium.

Let [C6H6O6-] = x, [H+] = x

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