step 1
Solve the first inequality
[tex]2x+3\leq5[/tex][tex]\begin{gathered} 2x\leq5-3 \\ 2x\leq2 \\ x\leq1 \end{gathered}[/tex]
the solution for the first inequality is the interval (-infinite,1]
step 2
Solve the second inequality
4x+1>17
4x>16
x>4
the solution for the second inequality is the interval (4, infinite)
therefore
the solution of the compound inequality is
(-infinite,1] U (4, infinite)
In a number line, the solution is
At x=1 is a closed circle and at x=4 is an open circle
