Answer :
Given data:
The given angle of elevation is θ= 68.9°.
The horizontal distance is d=116 m.
The expression for tanθ is,
[tex]\begin{gathered} \tan \theta=\frac{h}{d} \\ \tan (68.9^{\circ})=\frac{h}{116\text{ m}} \\ h=300.62\text{ m} \\ \approx301\text{ m} \end{gathered}[/tex]Thus, the height of the tower is 301 m.