Answer :
Take into account the following equivalences as conversion factors:
1 mi = 5280 ft
1 h = 60 min
Then, you have:
[tex]440\frac{ft}{\min}\cdot\frac{1mi}{5280ft}\cdot\frac{60\min }{1h}=5mph[/tex]Hence, the average rate is 5 miles per hour
Take into account the following equivalences as conversion factors:
1 mi = 5280 ft
1 h = 60 min
Then, you have:
[tex]440\frac{ft}{\min}\cdot\frac{1mi}{5280ft}\cdot\frac{60\min }{1h}=5mph[/tex]Hence, the average rate is 5 miles per hour