Answer :
Answer:
[tex]20.0\text{ L}[/tex]Explanation:
Here, we want to get the volume of NH3 that will react with 30L of NO at STP
From the question, we have it that 4 moles of ammonia reacted 6 moles of NO
Thus, we have the mole ratio as 6 to 4
Thus, the volume of ammonia reacted would be:
[tex]\frac{4}{6}\times30\text{ = 20.0 L}[/tex]