Answer :
a) A U (B ∩ C)
In order to obtain the result for the previous set, first find (B ∩ C)
∩ is the intersection operation (the result is a set with common elements in the implied sets) Based on the given sets, for interection operation, you get:
(B ∩ C) = {e , g}
Next, the union operation with A results (union operation results in a set with all values of both sets but without repeating elements):
A U (B ∩ C) = {c , d , e , f , g}
b) A' ∩ (B U C)
A' is the complement of A (all values of the universe not present in A). In this case:
A' = {a , b , g}
B U C = {a , c , e , f , g}
Then:
A' ∩ (B U C) = {a , g}
c) A i (B' ∩ C')
B' = {b , d , f}
C' = {a , b , c , d}
B' ∩ C' = {b , d}
Then:
A ∩ (B' ∩ C') = {d}