Given the following set of numbers,
[tex]68,\text{ 68, 70, 61, 67, 71, 63, 67}[/tex]
Where the (n) number of data is 8, the mean is,
[tex]\bar{x}=\frac{x_1+x_2+..._{}+x_n}{n}=\frac{68+68+70+61+67+71+63+67}{8}=66.875[/tex]
The standard deviation is 3.36
Hence, the interval that is 1 population within the mean is given by
[tex](66.88-3.36,66.88+3.36)=(63.52,70.24)[/tex]
Of all the data only 71, 61, and 63 are not an element of the interval (63.52,70.24)
The total number of data is 8.
Hence, the total number of data within 1 standard deviation of the mean is 5
