Answer :
Answer
A - Iodine is being oxidized
B - Cl2 is being reduced
Explanation
[tex]I_{2(s)}^0\text{ + 5Cl}_{2(g)}^0\text{ + 6H}_2O_{(l)}\rightarrow2HI^VO_{3(aq)}\text{ + HCl}_{(aq)}^{-I}[/tex]Answer
A - Iodine is being oxidized
B - Cl2 is being reduced
Explanation
[tex]I_{2(s)}^0\text{ + 5Cl}_{2(g)}^0\text{ + 6H}_2O_{(l)}\rightarrow2HI^VO_{3(aq)}\text{ + HCl}_{(aq)}^{-I}[/tex]