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Answer :

[tex]\frac{25a^{-5}b^{-8}}{5a^4b}=\frac{25}{5}\times a^{-5-4}\times b^{-8-1}[/tex][tex]\frac{25a^{-5}b^{-8}}{5a^4b}=5\times a^{-9}\times b^{-9}[/tex][tex]\frac{25a^{-5}b^{-8}}{5a^4b}=\frac{5}{a^9b^9}[/tex]

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