Since the distanc function is given by
[tex]d(t)=\frac{1}{2}gt^2[/tex]
in order to find the distance at 8 seconds, we need to substitute t=8 into this function, that is,
[tex]d(8)=\frac{1}{2}g(8)^2[/tex]
By taking into account that g=32 ft/sec^2, we have
[tex]d(8)=\frac{1}{2}(32)(64)[/tex]
which gives
[tex]\begin{gathered} d(8)=16\times64 \\ d(8)=1024 \end{gathered}[/tex]
Therefore, the answer is 1024 ft, which corresponds to the last option.
