Recall that:
[tex](f\cdot g)(x)=f(x)\cdot g(x)\text{.}[/tex]
Substituting f(x)=x+4 and g(x)=3x²-7 we get:
[tex]\begin{gathered} (f\cdot g)(x)=_{}(x+4)(3x^2-7), \\ (f\cdot g)(x)=3x^3-7x+12x^2-28, \\ (f\cdot g)(x)=3x^3+12x^2-7x-28. \end{gathered}[/tex]
Answer: Option B.
