👤

Answer :

we have the number

[tex]6-\sqrt[]{-40}[/tex]

Remember that

i^2=-1

so

substitute

[tex]6-\sqrt[]{(i^2)40}[/tex][tex]6-2i\sqrt[]{10}[/tex]

therefore

the real part is 6

the imaginary part is -2√10

Go Teaching: Other Questions