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The figure shows a straight path crossing a circular garden. The equation of the circular garden is x2 + y2 = 49 and the equation of the path is given by y = 2x + 7. Find the points at which the path cuts the circular garden.

The Figure Shows A Straight Path Crossing A Circular Garden The Equation Of The Circular Garden Is X2 Y2 49 And The Equation Of The Path Is Given By Y 2x 7 Find class=

Answer :

Answer:

(0, 7) and (-28,5, -21/5)

Explanation:

To find the points of intersection

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