There are 6 square, 3 circles and 2 triangle on left side of hanger so equation is,
[tex]\begin{gathered} 6\cdot2+3\cdot3+2\cdot t=12+9+2t \\ 21+2t \end{gathered}[/tex]
There are 3 squares, 2 circles and 5 triangles in right side portion of hanger. So equation for right portion is,
[tex]\begin{gathered} 3\cdot2+2\cdot3+5t=6+6+5t \\ =12+5t \end{gathered}[/tex]
The hanger is balanced on both side means both equation is equal to each other. So equation for the hanger is,
[tex]21+2t=12+5t[/tex]
Correct options are 1, 2 and 5 options.
