Given the central angle of the arc is angle GHJ which is equal to 60 degrees and the radius of the circle is 5 units.
Now, the area of the sector GHJ is obtained as follows:
[tex]\begin{gathered} A=\frac{60}{360}\times\pi r^2 \\ =\frac{1}{6}\times\frac{22}{7}\times5\times5 \\ =13.09 \end{gathered}[/tex]
The area of the sector is 13.09 unit^2.
