Solution:
Given;
[tex]\sqrt{16}\cdot\sqrt{4}[/tex][tex]\sqrt{16}\cdot\sqrt{4}[/tex]
We can simplify the perfect square as;
[tex]\begin{gathered} \sqrt{16}\cdot\sqrt{4}=\sqrt{4\times4}\cdot\sqrt{2\times2} \\ \\ \sqrt{16}\cdot\sqrt{4}=4\cdot2 \\ \\ \sqrt{16}\cdot\sqrt{4}=8 \end{gathered}[/tex]
CORRECT OPTION: C
