Given: The dimension of the right-trinagle as
[tex]\begin{gathered} H_{\text{ypothenuse}}=24\text{inches} \\ O_{ne\text{ of the legs of the triangle}}=12inches \end{gathered}[/tex]
To Determine: The second leg of the triangle to the nearest tenth
Solution:
Let us represent the given using a right-triangle
The hypothenuse is the logest side and the side facing the right angle
Applying pythagoras theorem which state that the square of the hypothenuse is equal to the sum of the squares of the other sides
Let the other leg be y
Therefore
[tex]y^2+12^2=24^2[/tex][tex]\begin{gathered} y^2+144=576 \\ y^2=576-144 \\ y^2=432 \end{gathered}[/tex][tex]\begin{gathered} y^2=432 \\ y=\sqrt[]{432} \\ y=20.7846 \\ y\approx20.8inches \end{gathered}[/tex]
Hence, the second leg of the triangle is 20.8 inches rounded to the nearest tenth
