Answer :
Given a system of equations 5x+2y=10 and 3x+y=6.
From the second equation, we have y=6-3x. Now, substitute y=6-3x in the first equation and solve as follows:
[tex]\begin{gathered} 5x+2(6-3x)=10 \\ 5x+12-6x=10 \\ -x=10-12 \\ -x=-2 \\ x=2 \end{gathered}[/tex]If x=2, then y=6-3(2)=6-6=0.
Thus, the ordered pair is (2,0)