Answer :
Given the equation :
[tex](x-h)^2+(y-k)^2=r^2[/tex]The given equation is the general form for the equation of the circle :
So, the center of the circle = ( h , k )
And the radius of the circle = r
Given the equation :
[tex](x-h)^2+(y-k)^2=r^2[/tex]The given equation is the general form for the equation of the circle :
So, the center of the circle = ( h , k )
And the radius of the circle = r