To draw any line on the plane, locate two points on it and cross them using a straight line.
Then, in our case, we need to find two points on each of the two lines
As for y= -x-3
[tex]\begin{gathered} x=0 \\ \Rightarrow y=-0-3=-3 \\ \Rightarrow(0,-3) \\ x=1 \\ \Rightarrow y=-1-3=-4 \\ \Rightarrow(1,-4) \end{gathered}[/tex]
Similarly, in the case of x-3y=-3
[tex]\begin{gathered} x=0 \\ \Rightarrow0-3y=-3 \\ \Rightarrow y=1 \\ \Rightarrow(0,1) \\ x=-3 \\ \Rightarrow-3-3y=-3 \\ \Rightarrow y=0 \\ \Rightarrow(-3,0) \end{gathered}[/tex]
Using the first set of points, graph y= -x-3, as shown below
Graphing the second line, x-3y=-3
Graph both lines at the same time and look for the intersection point
Then, the solution to the system of equations is (x,y)=(-3,0)
