The given function is
[tex]f(x)=\frac{x+7}{3x+4}[/tex]
To find f(x + 1), substitute x in f by (x + 1)
[tex]f(x+1)=\frac{(x+1)+7}{3(x+1)+4}[/tex]
Simplify it
[tex]\begin{gathered} f(x+1)=\frac{x+1+7}{3x+3+4} \\ \\ f(x+1)=\frac{x+8}{3x+7} \end{gathered}[/tex]
The answer is
[tex]f(x+1)=\frac{x+8}{3x+7}[/tex]
