Answer :
The given expression is
[tex]x^2-5x+2=-4x+5[/tex]First, let's move all the terms to the left side
[tex]x^2-5x+4x+2-5=0[/tex]Then, we reduce like terms
[tex]x^2-x-3=0[/tex]To find the x-intercepts, we use the quadratic formula
[tex]x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]Where a = 1, b = -1, and c = -3. Let's replace these values
[tex]\begin{gathered} x_{1,2}=\frac{-(-1)\pm\sqrt[]{(-1)^2-4(1)(-3)}}{2(1)}_{} \\ x_{1,2}=\frac{1\pm\sqrt[]{1+12}}{2}=\frac{1\pm\sqrt[]{13}}{2} \\ x_1=\frac{1+\sqrt[]{13}}{2}\approx2.3 \\ x_2=\frac{1-\sqrt[]{13}}{2}\approx-1.3 \end{gathered}[/tex]