We have the following:
6.
[tex]0.2\cdot(4n+3)=2.2[/tex]
solve for n:
[tex]\begin{gathered} 0.8n+0.6=2.2 \\ 0.8n=2.2-0.6 \\ n=\frac{0.16}{0.8} \\ n=2 \end{gathered}[/tex]
The answer is 2.
7.
[tex]\begin{gathered} \frac{9+t}{12}=-3 \\ \end{gathered}[/tex]
solving for t:
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