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Answer :

We begin by balancing the equation by trial and error. We will start by balancing the hydrogens. We have 2 hydrogens on the reactants side, so we will write the coefficient 2 before HNO2:

[tex]H_2SO_4+Na_{}NO_2\rightarrow2HNO_2+Na_2SO_4[/tex]

Now we will continue with the sodium. On the product side, we have two sodium atoms. To balance it we put the coefficient 2 before NaNO2:

[tex]H_2SO_4+2Na_{}NO_2\rightarrow2HNO_2+Na_2SO_4[/tex]

Let's count how many atoms we have of each element:

We have the same number of atoms of each element on each side of the reaction, so the equation is balanced. Now the draw of the molecules is:

View image KalelV553108
View image KalelV553108
View image KalelV553108

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