Answer :
The apparent mass m is related to the actual mass m_0 by:
[tex]m=\frac{m_0}{\sqrt{1-\frac{v^2}{c^2}}}[/tex]Isolate v:
[tex]v=c\sqrt{1-\left(\frac{m_0}{m}\right)^2}[/tex]Replace m=1.0311m_0:
[tex]v=c\sqrt{1-\left(\frac{m_0}{1.0311m_0}\right)^2}=0.24375...c\approx7.3\times10^6\frac{m}{s}[/tex]Therefore, the speed of the object is approximately 7.3*10^6 m/s.