Using the slope form equation
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ m=\text{slope} \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{6-4}{12-4} \\ m=\frac{2}{8}=\frac{1}{4} \\ \text{ using the point (4,4)} \\ y-4=\frac{1}{4}(x-4) \\ \end{gathered}[/tex]
Using the second point (12, 6)
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-6=\frac{1}{4}(x-12) \end{gathered}[/tex]
The answer is D and E.
