Solution
The following are all 5 quiz scores of a student in a statistics course. Each quite was graded on a 10-point scale
Where, n = 5
[tex]9,10,9,8,9[/tex]
To find the standard deviation, firstly we will find the mean
[tex]Mean=\frac{9+10+9+8+9}{5}=\frac{45}{5}=9[/tex]
Secondly, we will subtract the mean from each score
The standard deviation will be
[tex]\sigma=\sqrt{\frac{\sum^(x-mean)^2}{n}}=\sqrt{\frac{2}{5}}=\sqrt{0.4}=0.63\text{ \lparen two decimal places\rparen}[/tex]
Hence, the standard deviation is 0.63 (two decimal places)
