Given that the work done is W = 3 J.
The charge given is q = 0.5 C
We have to find the voltage.
The voltage can be calculated by the formula
[tex]V\text{ = }\frac{W}{q}[/tex]
Substituting the values, the voltage will be
[tex]\begin{gathered} V=\text{ }\frac{3}{0.5} \\ \text{ = }6\text{ V} \end{gathered}[/tex]
Thus, the magnitude of voltage is 6 V
