Given the following expression:
[tex]\frac{1-\frac{1}{x}}{3+\frac{1}{x}}[/tex]
We will simplify the given expression as follows:
Multiply both the numerator and the denominator by x to eliminate the denominators of each part
[tex]\frac{1-\frac{1}{x}}{3+\frac{1}{x}}=\frac{x(1-\frac{1}{x})}{x(3+\frac{1}{x})}=\frac{x-x*\frac{1}{x}}{3x+x*\frac{1}{x}}=\frac{x-1}{3x+1}[/tex]
So, the answer will be:
[tex]\frac{x-1}{3x+1}[/tex]
