Given:
[tex]y=4^x+1[/tex]
When x=0,
[tex]y=4^0+1[/tex][tex]y=2[/tex]
When x=1,
[tex]\begin{gathered} y=4+1 \\ y=5 \end{gathered}[/tex]
When x=2,
[tex]\begin{gathered} y=4^2+1 \\ y=17 \end{gathered}[/tex]
When x=-1,
[tex]\begin{gathered} y=4^{-1^{}}+1 \\ y=\frac{1}{4}+1 \\ y=1.25 \end{gathered}[/tex]
When x=-2,
[tex]\begin{gathered} y=4^{-2}+1 \\ y=\frac{1}{4^2}+1 \\ y=1.0625 \end{gathered}[/tex]
Option A is the correct answer.
