hello can you help me solve this trigonometry problem and in the question it notes report answer accurate to a 4 decimal places (do not use pi or the sign of pi for this problem)

Let's begin by listing out the information given to us:
[tex]\theta=4.07,r=3.4\operatorname{cm}[/tex]The area of a sector is given by the formula:
[tex]\begin{gathered} A=\frac{1}{2}r^2\theta \\ where\colon\theta=radians \end{gathered}[/tex]We will sustitute the values for central angle & radius into the formula to solve
[tex]\begin{gathered} A=\frac{1}{2}r^2\theta \\ \theta=4.07,r=3.4\operatorname{cm} \\ A=\frac{1}{2}\cdot3.4^2\cdot4.07 \\ A=\frac{1}{2}\cdot47.0492=23.5246 \\ A=23.5246\operatorname{cm}^2 \end{gathered}[/tex]