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Answer :

[tex]\frac{(5w^2+2)}{3p}[/tex]

For w=4 and p=3

Simply replace w by 4 and p by 3 in the equation , and solve:

[tex]\frac{(5\times4^2+2)}{3(3)}[/tex][tex]\frac{5\times16+2}{9}[/tex][tex]\frac{80+2}{9}[/tex][tex]\frac{82}{9}[/tex][tex]9.11[/tex]

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