We shall use the relation:
[tex]\theta=\frac{\beta-\alpha}{2}[/tex]
Therefore, we have
[tex]\begin{gathered} m\angle C=\frac{NH-MF}{2} \\ \\ m\angle C=\frac{132-42}{2} \\ \\ m\angle C=\frac{90}{2} \\ \\ m\angle C=45\degree \end{gathered}[/tex]
Then the angle m∠C is 45 degrees
