Answer:
[tex]w(t)=0.8(x-1)+18.7[/tex]
Explanation:
If we plot the points in a graph, we can see that they form a line:
Then, we can use the point-slope form of a line.
The slope-point form of a line, given a point P, is:
[tex]\begin{gathered} P=(x_P,y_P) \\ f\mleft(x\mright)=m\lparen x-x_P)+y_P \end{gathered}[/tex]
Where
m is the slope
(x_P, y_P) are the coordinates of a point.
To find the slope, we need two points P and Q:
[tex]\begin{gathered} \begin{cases}P=(x_P,y_P) \\ Q=(x_Q,y_Q)\end{cases} \\ . \\ m=\frac{y_P-y_Q}{x_P-x_Q} \end{gathered}[/tex]
Let's take the points:
P = (1, 18.7)
Q = (2, 19.5)
Then, using the formula for the slope:
[tex]m=\frac{18.7-19.5}{1-2}=\frac{-0.8}{-1}=0.8[/tex]
Now, using the slope-point form of a line, with m = 0.8 and P = (1, 18.7):
[tex]w(t)=0.8(x-1)+18.7[/tex]