Given:
There are four cards numbered
[tex]5,\text{ }6,\text{ }7,\text{ }8[/tex]
Required:
We have to find the probability of picking an 8 and then picking a 5.
Explanation:
The possibility of picking an 8 in the first time is 1 out of the four cards.
Therefore the probability of picking an 8 first is
[tex]\frac{1}{4}[/tex]
Now since you did not put the card back so there are three cards now.
So the possibility of picking a 5 in the second time out of the three cards is 1.
Therefore the probability of picking a 5 in the second time is
[tex]\frac{1}{3}[/tex]
Now we multiply both the probabilities to find the required answer.
Hence the probability of picking an 8 and then a 5 is
[tex]\frac{1}{4}\times\frac{1}{3}=\frac{1}{12}[/tex]
Final answer:
Hence the final answer is
[tex]\frac{1}{12}[/tex]
