Answer :
We have the following:
[tex]z+4\mleft(2z+3\mright)=15[/tex]solving for z:
[tex]\begin{gathered} z+8z+12=15 \\ 9z=15-12 \\ z=\frac{3}{9} \\ z=\frac{1}{3} \end{gathered}[/tex]The answer is B. z = 1/3
We have the following:
[tex]z+4\mleft(2z+3\mright)=15[/tex]solving for z:
[tex]\begin{gathered} z+8z+12=15 \\ 9z=15-12 \\ z=\frac{3}{9} \\ z=\frac{1}{3} \end{gathered}[/tex]The answer is B. z = 1/3