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Answer :

We will determine the current as follows:

[tex]I=\frac{V}{R}[/tex]

[tex]\begin{gathered} I=\frac{114V}{54\Omega}\Rightarrow I=\frac{19}{9}A \\ \\ \Rightarrow I\approx2.11A \end{gathered}[/tex]

So, the current is 19/9 Amps, that is approximately 2.11 Amps.

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