Step 1
Given;
[tex]\begin{gathered} Two\text{ parrallelograms have ratio }\frac{6}{5} \\ The\text{ perimeter of the larger figue is 72 units} \end{gathered}[/tex]
Required; To find the perimeter of the smaller figure,
Step 2
We will use the ratio below;
[tex]\frac{6}{5}=\frac{72}{Perimeter\text{ of small figure}}[/tex][tex]\begin{gathered} 6(perimeter\text{ of small figure\rparen=72\lparen5\rparen} \\ Perimeter\text{ of small figure=}\frac{72(5)}{6} \\ Perimeter\text{ of small figure=60units} \end{gathered}[/tex]
Answer;
[tex]Perimeter\text{ of small figure=60unit}^s[/tex]
