Answer :
We have to write an equation of a line with a slope of 1/3 and passes through the point (3,2).
We can write the equation in slope-point form:
[tex]y-y_0=m(x-x_0)[/tex]In this case, m=1/3 and (x0,y0)=(3,2). Then, the equation becomes:
[tex]\begin{gathered} y-2=\frac{1}{3}(x-3) \\ y=\frac{1}{3}x-1+2 \\ y=\frac{1}{3}x+1 \end{gathered}[/tex]Answer:
Point-slope form: y-2=(1/3)*(x-3)
Slope-intercept form: y=(1/3)*x+1