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A ball is initially moving at 6 m/s up a ramp. The acceleration of the ball is -2 m/s/s down the ramp. What is the balls velocity after 10 seconds? (frame of reference + is up the ramp)

Answer :

Dedulja66letgo

Answer:

V = - 14 m/s

Explanation:

Given:

V₀ = 6 m/s

a = - 2 m/s

t = 10 s

_____________

V - ?

According to the formula:

V = V₀ + a·t

V = 6 - 2·10 = - 14 m/s

(The ball rolls down an inclined plane)

Jcherry99go

Answer:

Explanation:

Comment

This is an example using a = (vf - vi)/t where

  • a is the acceleration                (-2 m/s^2
  • vr is the final velocity               (This is what we are solving for)
  • t is the time = 10 seconds         (in seconds )
  • vi = 6 m/s                                  (the initial velocity)

Solution

a = (vf - vi)/t                                 Substitute the givens into the formula

-2m/s^2 = (vf - 6 m/s)/10 sec     multiply both sides by 10

- 2 * 10 = 10(vf - 6) / 10               Combine

-20 = vf - 6                                 Add 6 to both sides

-20 + 6 = vf - 6 + 6

- 14 =vf

This means the ball is going down the ramp.

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