Answer :
The point-slope form of the linear equation is
[tex]y-y_1=m(x-x_1)[/tex]m is the slope
(x1, y1) is a point on the line
Since the slope of the line is -6, then
m = -6
Since the line passes through the point (-5, 15), then
[tex]\begin{gathered} x_1=-5 \\ y_1=15 \end{gathered}[/tex]Substitute them in the form of the equation above
[tex]\begin{gathered} y-15=-6(x-\lbrack-5\rbrack) \\ y-15=-6(x+5) \end{gathered}[/tex]The answer is
[tex]y-15=-6(x+5)[/tex]