Answer :
[tex]\begin{gathered} \text{There are two terms involved in this product.} \\ \sqrt[]{3\text{ }}is\text{ an irrational number because 3 is not a perfect square} \\ 2\text{ is a rational number} \\ \text{their product, 2}\sqrt[]{3}\text{ is an irrational number as well.} \end{gathered}[/tex]
This leaves us with option B