Answer :
Let x be the first, number and y be the second, then we can set the following system of equations:
[tex]\begin{gathered} x+5y=36, \\ x-2y=1. \end{gathered}[/tex]Subtracting the second equation from the first one, and solving for y we get:
[tex]\begin{gathered} x+5y-x+2y=36-1, \\ 7y=35, \\ \frac{7y}{7}=\frac{35}{7}, \\ y=5. \end{gathered}[/tex]Substituting y=5 in the second equation, and solving for x we get:
[tex]\begin{gathered} x-2(5)=1, \\ x=1+10, \\ x=11. \end{gathered}[/tex]Answer: The first number is 11 and the second one is 5.