Evaluate the function f(x) = x2 + 5x + 4 when x:{-4, -2,0, 1, 3, 5}

Answer:
Explanation:
Here, we want to get the values of f(x) at the given values of x
To get that, we have to substitute the values of x into f(x)
We take the x-values one after the other
when x = -4:
[tex]f(-4)=(-4)^2+5(-4)\text{ + 4 = 0}[/tex]when x = -2:
[tex]f(-2)=(-2)^2+5(-2)\text{ + 4 = -2}[/tex]when x = 0:
[tex]f(0)=0^2+5(0)\text{ + 4 = 4}[/tex]when x = 1:
[tex]f(1)=1^2+5(1)\text{ + 4 = 10}[/tex]when x = 3:
[tex]f(3)=3^2+5(3)\text{ + 4 = 28}[/tex]when x = 5:
[tex]f(5)=5^2+5(5)\text{ + 4 = 54}[/tex]For the given values of x:
[tex]f(x)\colon\mleft\lbrace0,-2,4,10,28,54\mright\rbrace[/tex]