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Mathematics

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if the perimeter of a rectangle measures 50 feet and the length of the rectangle is 17 feet, what is the width

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[tex]\begin{gathered} \text{Perimeter}=2(\text{length}+\text{width)} \\ 50=2(17+\text{width)} \\ 17+\text{width}=\frac{50}{2} \\ \text{width}=25-17 \\ \text{width}=8\text{feet} \end{gathered}[/tex]

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