Answer:
[tex]134.21g\text{ of C}_2H_4\text{ is needed}[/tex]
Explanation:
Here, we want to calculate the mass of ethene needed
From the balanced equation of reaction:
1 mole of ethene needed 3 moles of oxygen
x moles of ethene will need 14.38 moles of oxygen
To get the value of x, we have it that:
[tex]\begin{gathered} 1\times14.38\text{ = 3}\times x \\ x\text{ = }\frac{14.38}{3} \\ \\ x\text{ =4.793 moles} \end{gathered}[/tex]
To get the mass needed, we have to multiply the number of moles by the molar mass of ethene
The molar mass of ethene is 28 g/mol
Thus, we have the needed mass as:
[tex]\begin{gathered} Mass\text{ = number of moles }\times\text{ molar mass} \\ Mass\text{ = 4.793 }\times\text{ 28 = 134.21 g} \end{gathered}[/tex]
