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Answer :

[tex]\begin{gathered} \text{if f(0)= -4 and f(3)=6} \\ \\ f(x)=ax+b \\ \\ b=-4 \\ \\ f(3)=a(3)-4 \\ 6=a(3)-4 \\ 6+4=a(3) \\ \\ 10=a3 \\ a=\frac{10}{3} \\ \\ f(x)=\frac{10}{3}x-4 \end{gathered}[/tex]

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