Given,
The measure of sides of the rectangle is 4 inches and 4 inches.
The measure of diameter of the semicircle is 4 inches.
The area of the figure is,
[tex]\begin{gathered} \text{Area}=\text{area of rectangle+area of semicircle} \\ =\text{length}\times breadth+\frac{\pi}{2}\times(radius)^2 \\ =4\times4+\frac{\pi}{2}\times(2)^2 \\ =16+2\times3.14 \\ =16+6.28 \\ =22.28in^2 \end{gathered}[/tex]The perimeter of the figure is,
[tex]\begin{gathered} \text{perimeter}=\text{sum of thr}ee\text{ sides of rectangle+length of curve line} \\ =\text{4+4+4}+\frac{2\pi r}{2} \\ =12+3.14\times(2) \\ =12+2\times3.14 \\ =12+6.28 \\ =18.28in^{} \end{gathered}[/tex]Hence, option D is correct.